Suzanne asked me explain the solution to the final problem in last issue's IQ test. Here it is:
A fish has a head 9" long. The tail is equal to the size of the head plus one-half the size of the body. The body is the size of the head plus the tail. How long is the fish?
First, let's translate this into algebra. H = length of head, T = length of tail, and B = length of body. We are trying to determine H+B+T.
H = 9
T = H + B/2 = 9 + B/2
B = H + T = 9 + 9 + B/2 = 18 + B/2
So, if B = 18 + B/2 then:
{sub 18 from both sides} B-18 = B/2
{mult both sides by 2} 2B-36 = B
{sub B from both sides} B-36 = 0
{add 36 to both sides} B = 36
If B=36 then T = 9+B/2 = 27
So the total length of the fish = Head + Body + Tail = 9 + 36 + 27 = 72.
For those of you fretting over any of the other questions, here are the answers. (I obtained them by cracking the program and peering inside ):
1-2
2-5
3-4
4-3
5-2
6-2
7-5
8-5
9-3
10-5
11-3
12-2
13-4
14-5
15-5
16-4
17-2
18-4
19-4
20-4
21-4
22-2
23-3
24-2
25-2
26-2
27-4
28-3
29-3
30-5
31-4
32-3
33-2
34-3
35-2
36-4
37-2
38-4
39-4
40-3
41-4
42-2
43-5
44-1
45-2
46-4
47-4
48-3
49-5
50-2
51-4
52-2
53-2
54-5
55-3
56-1
57-5
58-5
59-3
60-4
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